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Question 3: demonstration

From 0 to , K1 and K¢2 are ON

We thus have:

From to : K¢1 and K2 are ON

We thus have:

With , the expression of the current during the interval it's the same as during the interval .

Therefore, the frequency of the current is the double of the current's frequency (the period is turned into half).

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Last update: 2005, September, 30 | Translation: Sergiu Ivanov